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ZanzabumX [31]
2 years ago
9

A circle with radius of 9 cm sits inside a circle with radius of 11

Mathematics
1 answer:
saul85 [17]2 years ago
8 0
Ok so to answer this, we first need to figure out the area of both circles
we will use the formula A=πr²

so our two areas end up being 121π and 81π

now all we do is subtract the smaller from the larger

121π - 81π = 40π

shaded region = 40π
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Answer:

The correct answer is "2.633< \sigma < 4.480".

Step-by-step explanation:

Given:

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now,

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    =20

⇒ x^2_{\frac{\alpha}{2}, n-1 } = x^2_{\frac{0.9}{2}, 21-1 }

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The 90% Confidence interval will be:

= \sqrt{\frac{(n-1)s^2}{x^2_{\frac{\alpha}{2}, n-1 }} } < \sigma < \sqrt{\frac{(n-1)s^2}{x^2_{1-\frac{\alpha}{2}, n-1 }}

= \sqrt{\frac{(21-1)3.3^2}{31.410} } < \sigma < \sqrt{\frac{(21.1)3.3^2}{10.851} }

= \sqrt{\frac{20\times 3.3^2}{31.410} } < \sigma < \sqrt{\frac{20\times 3.3^2}{10.851} }

= 2.633< \sigma < 4.480

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