Assume that the length of the rectangle is "l" and that the width is "w".
We are given that:
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15
Substitute with w in equation I to get the length as follows:
l = 2w + 1
l = 2(15) + 1
l = 30 + 1 = 31
Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
Shown Where? You didnt add a picture of a graph
The maximum volume would be when the bottom of the box is a square.
The perimeter of the bottom is 36, so the side of the square would be 36/4 = 9 cm.
Then to find volume multiply the length by the width by the height:
Volume = 9 x 9 x 4 = 324 cm^3
The answer would be a.
Answer:
Step-by-step explanation:
The form, y = mx + b is the slope intercept form of a straight line.
Where b = intercept
m = slope = (change in the value of y in the vertical axis) / (change in the value of x in the horizontal axis.
Slope = (y2 - y1)/(x2 - x1)
y2 represents final value of y = - 3
y1 represents initial value of y = 3
x2 represents final value of x = 3
x1 represents initial value of x = 0
Therefore,
slope = (- 3 - 3)/(3 - 0) = - 6/3 = - 2
To determine the intercept, we would substitute m = - 2, x = 3 and y = -3 into y = mx + b. It becomes
- 3 = - 2 × 3 + b = - 6 + b
b = - 3 + 6 = 3
The equation becomes
y = - 3x + 3
Answer:
The length of Mai's bike ride was 2.1 times the length of Noah's ride.
Step-by-step explanation:
Mai biked 5 1/4 miles today
So he biked, in miles:

Noah biked 2 1/2 miles.
So, in miles, he biked:

How many times the length of Noah’s bike ride was Mai’s bike ride?
We divide the Mai distance by Noah's distance. In a division of fractions, we multiply the numerator by the inverse of the denominator. So

The length of Mai's bike ride was 2.1 times the length of Noah's ride.