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kozerog [31]
3 years ago
14

(-3u^2+7u-2)+(4u^2+6u+1)

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

(-3u^2 + 7u - 2) + (4u^2 + 6u + 1)

= -3u^2 + 7u - 2 + 4u^2 + 6u + 1

= 4u^2 - 3u^2 + 7u + 6u + 1 - 2

= u^2 + 13u - 1


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the sum of 3 decimal numbers is 6. Exactly one of the numbers is less than 1 what could those numbers be.
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Now I'll subtract 0.7 from both sides to see what y and z have to add up to.

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