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jasenka [17]
4 years ago
8

What is the difference of the rational expressions below?

Mathematics
1 answer:
Stolb23 [73]4 years ago
7 0

Answer: A

Step-by-step explanation:

We need to get the denominators to be same first before we can do anything to the numerator.

<em>The LCD (lowest common denominator) is </em>3x^{3}<em>. To find the LCD, multiply the denominators together: </em>x^{3}<em> · </em>3x<em> = </em>3x^{3.

Below, we are trying to get the denominators to equal the same or to 3x^{3}.

\frac{3}{3}  (\frac{4}{x^{3} } ) - \frac{x^{2} }{x^{2} }  (\frac{2x-1}{3x} )

\frac{12}{3x^{3} } - \frac{2x^{3}-x^{2} }{3x^{3} }

Now that the denominators are the same, we can subtract the numerators from each other.

\frac{ 12 - (2x^{3} -x^{2})\\}{3x^{3} } \\

\frac{12-2x^{3} +x^{2} }{3x^{3} }

Now, we can just reorganize the variables.

Answer:  A or \frac{-2x^{3} + x^{2}+12 }{3x^{3} }

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