Ask question

Ask question

All categories

4 years ago

12

Quadrilateral ABCD is reflected across the x-axis and then reflect across the y-axis to form quadrilateral A′B′C′D′. If the coor

dinates of vertex A are (-7, 3), what are the coordinates of vertex A′?

1 answer:

Elenna [48]4 years ago

5 0

The answer should be (7, -3). Good luck!

You might be interested in

You and a friend went to the movies. You decide to get some snacks. You got 2 boxes of candy that cost $3.49 for each box. You a

Dima020 [189]

Answer:

You and your friend spent $17.30 together

Step-by-step explanation:

3.49 x 2 = 6.98

6.98 + 4.82 = 11.8

11.8 + 5.50 = 17.3

3 0

3 years ago

The equation 4(x – 3)2 – 5 = 139 has two solutions: one positive and one negative. What is the

AlekseyPX

Answer:

Step-by-step explanation:

4(x-3)2-5 = 139

(4x-12)-5=139

-20x + 60 = 139

-20x +60 - (60) = 139- 60

-20x = 79 divide both sides by -20

x = -3.95

3 0

3 years ago

Find the surface area of the rectangular prism.

olganol [36]

Answer:

D. 270 cm2

Step-by-step explanation:

2*(15*5 + 15*3 + 5*3) = 270 cm2

8 0

3 years ago

Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30

Dafna11 [192]

Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

$\bf u=
\begin{cases}
x=7cos(330^o)\\
\qquad 7\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{7\sqrt{3}}{2}\\
y=7sin(330^o)\\
\qquad 7\cdot -\frac{1}{2}\\
\qquad -\frac{7}{2}
\end{cases}\qquad \qquad v=
\begin{cases}
x=8cos(30^o)\\
\qquad 8\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{8\sqrt{3}}{2}\\
y=8sin(30^o)\\
\qquad 8\cdot \frac{1}{2}\\
\qquad 4
\end{cases}$

$\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)
\\\\\\
\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~ \stackrel{b}{\frac{1}{2}}\right)\\\\
-------------------------------$

$\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}
\\\\\\
\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o$

8 0

3 years ago

classmate DAN sual For madenaldy asymmetrical distribution, the arithmetic mean 28 and the median = 25. Find modo of this dish b

vazorg [7]

Median=M_d=25
Mean=M=28
Mode=M_o=?

We know

$\boxed{\sf M_o=3M_d-2M}$

$\\ \sf\longmapsto M_o=3(25)-2(28)$

$\\ \sf\longmapsto M_o=75-56$

$\\ \sf\longmapsto M_o=19$

3 0

3 years ago