Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92
The 90th percentile score is nothing but the x value for which area below x is 90%.
To find 90th percentile we will find find z score such that probability below z is 0.9
P(Z <z) = 0.9
Using excel function to find z score corresponding to probability 0.9 is
z = NORM.S.INV(0.9) = 1.28
z =1.28
Now convert z score into x value using the formula
x = z *σ + μ
x = 1.28 * 92 + 1028
x = 1145.76
The 90th percentile score value is 1145.76
The probability that randomly selected score exceeds 1200 is
P(X > 1200)
Z score corresponding to x=1200 is
z = 
z = 
z = 1.8695 ~ 1.87
P(Z > 1.87 ) = 1 - P(Z < 1.87)
Using z-score table to find probability z < 1.87
P(Z < 1.87) = 0.9693
P(Z > 1.87) = 1 - 0.9693
P(Z > 1.87) = 0.0307
The probability that a randomly selected score exceeds 1200 is 0.0307
1.30 :)
All you have to do is see if the number on your left is greater than 5 or not if it’s is round up 1 if not it stays the same !
Hope this helped !!!
Answer:
-1
Step-by-step explanation:
-3(2) = -6 + 5 = -1
negative 8 because 45/-9 = -5
The equation of the slope is given by:
m = (y2 - y1) / (x2 - x1)
For GH we have:
m = (-4 - (-9)) / (-3 - 5)
m = (5) / (-8)
m = -5 / 8
For FH we have:
m = (-4 - 4) / (-3 - 2)
m = (-8) / (-5)
m = 8/5
Answer:
C) The slope of GH = - 5/8, and the slope of FH = 8/5; therefore, GH ⊥ FH