Answer:
The passenger train traveled at a speed of 25 miles/hour
Step-by-step explanation:
In this question, we are asked to calculate the rate at which a particular passenger train is traveling.
We use the information in the question to answer as follows;
Firstly, we identify that they traveled at the same time but their distances are different. This means that their speed must be different also.
Mathematically, we know that time can be calculated as distance/ time.
Let us say the speed at which the passenger train traveled is x miles per hour. This means that the speed of the freight train which was 5 miles per hour slower would be (x-5) miles per hour.
We know their times are equal;
Hence;
100/x = 80/(x-5)
We cross multiply
100(x-5) = 80x
100x -500 = 80x
100x-80x = 500
20x = 500
x = 500/20
x = 25 miles per hour
Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank
boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time
boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet
The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates
(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x
1100x + x^2 = 1400x + 700000
x^2-300x -700000 = 0 quadratic formula yields x = 1000
One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m
Answer:
C
Step-by-step explanation:
Answer:
The first one is x = 19
The second one is x = 17
Step-by-step explanation:
The first one:
(4x + 3) + (x - 8) = 90 ---> becasue the angle is 90 degrees
substitute 19 and check
The second one:
(7x + 10) + (3x) = 180 ---> because the angle is 180 degrees
substitute 17 and check
Hope this helps! :]
Answer:
The Answer is 77
Step-by-step explanation:
The data is going up by 7 every time, look for yourself, 56, 63, 70, 77.
I hope this helped! :)
