Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
24 x 35 = 840
Step-by-step explanation:
-1 1/5 + 3/4 = -0.45
1/5 is 0.2 in decimal form, and 3/4 is 0.75:
-1.2 + 0.75 = -0.45
Hope this helps!
Answer:50% red 4/42 ace
Step-by-step explanation: