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timurjin [86]
3 years ago
10

What go in the blank

Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

inverse

Step-by-step explanation:

¬ is the symbol for not.  When we have not a  implies not b  we have a inverse

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Which length is greater 1/2 meter or 240 centimeters explain
avanturin [10]

Solution:

we have been asked to find

Which length is greater 1/2 meter or 240 centimeters.

To compare the two given lengths, we will have to make both the length in same unit system.

Here 1/2 meter can be written as 50 centimeter , because 1 meter =100cm.

Now its very clear that 240 centimeters is more than 50 centimeters.

Hence we can say 240 centimeters is greater than 1/2 meter .

8 0
3 years ago
X+2y=4<br> 2x-2y=5 <br> what is the answer
Tom [10]

x + 2y = 4

2x - 2y = 5

Adding both the equations:

x + 2y + 2x - 2y = 9

3x = 9

x = 3

y = 4-x /2 = 1/2

4 0
3 years ago
A basket of food is sufficient to feed 10 persons for 3 days. How many days would it last for 5 persons? ​
lina2011 [118]

10persons = 3days

5 persons = 1.5 or 1 and hal f day

Hope it's helps

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5 0
3 years ago
What is 0.20833333333 as a fraction?
Greeley [361]

Answer:

20833/1000000

Step-by-step explanation:


5 0
4 years ago
A right cylinder has a radius of r inches and height of 2r inches.
lys-0071 [83]

Answer:

Part a) The lateral area is 4r^{2} \pi \ in^{2}

Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

Part c) The surface area is 6r^{2} \pi\ in^{2}

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

SA=LA+2B

where

LA is the lateral area

B is the area of the base of cylinder

we have

r=r\ in

h=2r\ in

Part a) Find the lateral area

The lateral area is equal to

LA=2\pi rh

substitute the values

LA=2\pi r(2r)

LA=4r^{2} \pi\ in^{2}

Part b) Find the area of the two bases together

The area of the  base B is equal to

B=r^{2} \pi\ in^{2}

so

the area of the two bases together is

2B=2r^{2} \pi\ in^{2}

Part c) Find the surface area of the cylinder

SA=LA+2B

we have

LA=4r^{2} \pi\ in^{2}

2B=2r^{2} \pi\ in^{2}

substitute

SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}

4 0
3 years ago
Read 2 more answers
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