Question

Solve by quadratic formula: 8a2 + 6a + 5=0

Answer 1

Answer:

$x = \frac{-3 \pm i\sqrt{31}}{8}$

Step-by-step explanation:

Quadratic Formula: $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

√-1 is imaginary number i

Step 1: Define Quadratic

8a² + 6a + 5 = 0

a = 8

b = 6

c = 5

Step 2: Plug into Quadratic Formula

$x = \frac{-6 \pm \sqrt{6^2-4(8)(5)} }{2(8)}$

Step 3: Solve

$x = \frac{-6 \pm \sqrt{36-160} }{16}$

$x = \frac{-6 \pm \sqrt{-124} }{16}$

$x = \frac{-6 \pm \sqrt{124} (\sqrt{-1} )}{16}$

$x = \frac{-6 \pm i\sqrt{124}}{16}$

$x = \frac{-6 \pm 2i\sqrt{31}}{16}$

$x = \frac{2(-3 \pm i\sqrt{31})}{16}$

$x = \frac{-3 \pm i\sqrt{31}}{8}$