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2 years ago

On Saturday Lindsay walked 3 1/2 mile in 1 and 2/5 hours what was her walking pace in miles per hour write in simplest form

Mathematics

1 answer:

Makovka662 [10]2 years ago

7 0

Answer:

If she walked 3.5 miles in 1.4 hours, then her pace was:

3.5 miles / 1.4 hours = 2.5 miles/hour

Step-by-step explanation:

To get her pace in miles per hour, you take the number of miles and divide by the number of hours.

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The length of each edge of a cube is decreased by 40 percent By what percent does the volume of the cube decrease? Express your

lora16 [44]

Answer:

78% (to the nearest tenth)

Step-by-step explanation:

Volume of a cube = (length )³

Let the length of the cube = y

Original volume = y³

if the length is decreased by 40%, then new length = 1- (40% of y)

= 1-0.4y

= 0.6%

New volume (after decreasing the length) = (0.6y)³

= 0.216‬‬y³

% Volume decrease = (Original volume - New volume)/Original Volume x 100%

= (y³ - 0.216‬‬y³)/ y³ x 100%

= 0.784y³/y³ x 100%

=78.4%

≈78%

5 0

3 years ago

Read 2 more answers

What are the dimensions for this triangle?

REY [17]

Answer:

2 and 2

Step-by-step explanation:

Parallel sides of rectangles are congruent, and because the other side of both rectangles is 2, the sides of the triangle are 2 because they share the side with the rectangle.

4 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$