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3 years ago

Complete the remainder of the

Mathematics

1 answer:

allsm [11]3 years ago

4 0

The corresponding values needed will be -23, -8, 7 and 22

<h3>Functions and Tables</h3>

Given the function y = 5x - 8

<h3>Get the domains and range</h3>

We are to get the range of the function for the given domains

If the value of x is -3

y = 5(-3) - 8

y = -15 - 8

y = -23

If the value of x is 0

y = 5(0) - 8

y = 0 - 8

y = -8

If the value of x is 3

y = 5(3) - 8

y = 15 - 8

y = 7

If the value of x is 6

y = 5(6) - 8

y = 30 - 8

y = 22

Hence the corresponding values needed will be -23, -8, 7 and 22

Learn more on tables of function here: brainly.com/question/3632175

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Answer:

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3 years ago

Read 2 more answers

Write the equation of the line that passes through the points (2, 3) and (3, -7). Put

FrozenT [24]

Answer:

$y - 3 = -10 (x-2)$

Step-by-step explanation:

The point-slope formula is $y-y_1 = m (x-x_1)$ . When knowing the slope of a line and a point it intersects, we can write its equation with that formula. Substitute $m$ , $x_1$ , and $y_1$ for real values.

1) First, find $m$ , or the slope. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ and substitute the x and y values of the given points. Then, solve:

$m = \frac{(-7)-(3)}{(3)-(2)} \\m = \frac{-7-3}{3-2} \\m = \frac{-10}{1} \\m = -10$

Therefore, the slope of the line is -10.

2) Now, substitute the needed real values into the point-slope formula, $y-y_1 = m (x-x_1)$ . Since $m$ represents the slope, substitute -10 in its place. Since $x_1$ and $y_1$ represent the x and y values of a point the line crosses, choose any of the points given and substitute its values into the formula. (Either one is fine, they both equal the same thing. I chose (2,3).) This will give the following answer and equation:

$y - 3 = -10 (x-2)$

7 0

3 years ago

A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.

S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

$x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)$