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coldgirl [10]
4 years ago
5

HELP PLZZZZZZZZZ!!!!!!!

Mathematics
1 answer:
Alona [7]4 years ago
7 0
The answer is D, DE=CE
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If you knew that the vertical intercept for a straight line was 150 and that the slope of the line was 4, then the dependent var
Maslowich

Answer:

Value of the independent variable = 25

Step-by-step explanation:

y-intercept form of a straight line is represented by the equation,

y = mx + b

here y = dependent variable

        m = slope

        b = y intercept or vertical intercept

        x = independent variable

In our question,

y-intercept 'b' = 150

slope of the line 'm' = 4

dependent variable y = 250

We will plug in these values in the equation of the line to get the value of the independent variable.

250 = 4x + 150

250 - 150 = 4x

x = \frac{100}{4}

x = 25

Therefore, value of the independent variable is 25.

7 0
4 years ago
CALC- limits<br> please show your method
gladu [14]
A. Factor the numerator as a difference of squares:

\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6

c. As x\to\infty, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4

e. Let's first rewrite the root terms with rational exponents:

\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}

Next we rationalize the numerator and denominator. We do so by recalling

(a-b)(a+b)=a^2-b^2
(a-b)(a^2+ab+b^2)=a^3-b^3

In particular,

(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3
(x^{1/2}-x)(x^{1/2}+x)=x-x^2

so we have

\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}

For x\neq0 and x\neq1, we can simplify the first term:

\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x

So our limit becomes

\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43
3 0
3 years ago
The equation y = 6.85x could represent a variety of different situations .
Marina86 [1]

Answer:

For every x feet of rope purchased, the total cost(y) increases by $6.85.

Step-by-step explanation:

4 0
3 years ago
What is 3.2258 rounded to the nearest thousandth?
Alexxx [7]

Answer:

3.3000

Step-by-step explanation:

hope this helps

may i get braineist pls?

8 0
2 years ago
Can someone help me out?
Elodia [21]

Answer:

Dark Blue

Step-by-step explanation:

I hope this helps with your question :)

7 0
3 years ago
Read 2 more answers
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