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stira [4]
3 years ago
8

cylinder has radius of 6 ft and height of 9 ft. how do you calculate the volume of a cone that fits exactly inside cylinder

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0
Couldn't you use pi • r^2•height That's the cylinder formula. Or you could use the cone formula pi•r^2•height/3
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Solve the equation: 2+3x=4+x(2+x)
grandymaker [24]
2 + 3x = 4 + 2x + x^2
x^2 - x + 2 = 0

(x - 0.5)^2 - 0.25 + 2 = 0

(x - 0.5)^2 = -1.75

x - 0.5 = +/- sqrt 1.75 * i

x = 0.5 + 1.32i  ,  0.5 - 1.32i  answer
4 0
3 years ago
Refer to the image i couldnt copy it so the image is the quesstion<br><br> answer in true or false
Irina18 [472]

The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.

<h3>Is the equation in the image correct or incorrect?</h3>

For a quadratic equation of the form:

y = a*x^2 + b*x + c

By using the Bhaskara's formula, the solutions of the equation:

0 = a*x^2 + b*x + c

Are given by the formula:

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}

Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.

So the equation shown in the image is incorrect.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

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6 0
2 years ago
An ellipse has a center at the origin, a vertex along the major axis at (20, 0), and a focus at (16, 0). the equation of the ell
olga_2 [115]
If the center is at (0, 0) and the vertex is at (20, 0), then the distance, a, is the length from the center to the vertex, 20.  The distance from the center to the focus is c.  The distance from the center to the focus is 16, so c = 16.  The formula we use to find the focus is c^2=a^2-b^2.  We have our c value and our a value, so we will sub in those to find b.  16^2=20^2-b^2 and 256 = 400 - b^2.  -b^2 = -144, so b = 12.  There you go!
5 0
3 years ago
Read 2 more answers
24 is 4 times as great as<br> Pls help
Vaselesa [24]

Answer:

6=k

Step-by-step explanation:

5 0
3 years ago
What integer values satisfy both inequalities? − 2 &lt; x &lt; 3 − 2 ≤ x &lt; 2
NARA [144]

Given:

The inequalities are:

-2

-2\leq x

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

-2

-2\leq x

For -2, the possible integer values are

x=-1,0,1,2          ...(i)

For -2\leq x, the possible integer values are

x=-2,-1,0,1        ...(ii)

The common values of x in (i) and (ii) are

x=-1,0,1

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

6 0
3 years ago
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