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3 years ago

The solution of the system is (400, 3,200). How would you interpret this solution?

Mathematics

2 answers:

ahrayia [7]3 years ago

4 0

Answer:

The solution of the system is the point where the graphs intersect, or have the same x and y values. This means that the company's cost to produce 400 caps is the same as the income made from selling 400 caps. Therefore, the company will not make a profit.Step-by-step explanation:

alekssr [168]3 years ago

3 0

The solution (400, 3, 200) is the answer to a system of equations which has three variables. Respectively, this system is expected to have three equations because it has three unknowns. So for example if your unknowns are x, y and z, then the answers will be x=400, y=3, and z=200.

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Other ways to write 50897

NARA [144]

Written form: fifty thousand eight hundred ninety-seven.

expanded form: 50000+800+90+7

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3 years ago

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Rite the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Lelechka [254]

-10, -10-2·1= -12, -10-2·2=-14, -10-2·3=-16, -10-2·4= -18, -10-2·5= -20,
-10-2·6= -22, -10-2·7 =-24, -10-2·8=-26, -10-2·9=-28

a=-10
d=-2
xn=a+d(n-1)

the first ten terms are
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3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

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3 years ago

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lions [1.4K]

Answer:

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Tasya [4]

Answer: 2/3, 1/2, 5/8,7/11

Step-by-step explanation: usually the smaller your denominator is the larger your fraction. You also have to look at the numerator and somewhat visualize what it would look like. Such as 2/3 is larger than 1/2 because 1/2 of 3 is 1.5 so since 2 is larger than 1.5 you can say 2/3 is larger

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3 years ago

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