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antoniya [11.8K]
2 years ago
13

Divide: 28.324 : 0.4 A 0.7081 B 7,081 C 708.1 D 70.81

Mathematics
2 answers:
zaharov [31]2 years ago
8 0

Answer:

D: 70.81

Step-by-step explanation:

valina [46]2 years ago
3 0

Answer:

D-70.81

Step-by-step explanation:

I did the math, this should be correct.

Good luck!

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An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
ra1l [238]
Earnings=20% of sales+7.5h+40

coeficinets are 7.5 and 0.2
vraiables are h and s
constant is 40

B. if h=25 and s=30 input,
7.5*25+0.2*300+40=$287.50


C
new equation is 9h+0.2s+40
coefienct woud be 9 and 0.2
variable is h and s
constant is 4

7 0
3 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

6 0
3 years ago
Please help this is due tomorrow.<br><br> 1/2 of 20?
Mars2501 [29]

1/2 of 20 is 20/2 which is 10.

All you really need to do here is to divide 20 by 2 to get 10.


6 0
3 years ago
Read 2 more answers
Work out the difference between 5/9and4/9
tatiyna

Answer:

1/9

Step-by-step explanation:

Subtract them

5/9-4/9=1/9 Answer

7 0
3 years ago
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