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juin [17]
3 years ago
9

The video states that 78% of people carry less than $50 in cash; 40% carry less than $20 in cash, and 9% carry no cash. Suppose

you have a random sample of 100 people and you check how much cash each person is carrying. Assuming that the percentages stated in the video are correct for all adult Americans, discuss how it could occur that 12 people in your sample are carrying no cash while only 75 people in your sample are carrying less than $50 in cash.
Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

The probability that 12 people in your sample are carrying no cash is 0.0712

Step-by-step explanation:

n = 100

p(no cash) = 0.09

x = 12

By applying binomial distribution

P(x,n) = nCx*px*(1-p)(n-x)

P(x = 12) = 0.074.

The probability that 12 people in your sample are carrying no cash is 0.074.

n = 100

p(less than 50) = 0.78

x = 75

By applying binomial distribution

P(x,n) = nCx*px*(1-p)(n-x)

P(x = 75) = 0.0712

The probability that 12 people in your sample are carrying no cash is 0.0712

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Answer: -1.1 , 2.4 , 1.51

Step-by-step explanation:

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3 years ago
Marci works at a hardware store. One cash flow estimate for their power tools department is $56,700, and the probability assessm
worty [1.4K]

Answer:

The given data represents, the 30% of TOTAL CASH INFLOW = $56,700 and it is in the power tools department.

Step-by-step explanation:

Here, according to the question:

The estimated cash flow of POWER TOOLS department  =  $56,700

Also, the probability assessment = 30%

So, the given 30% determines the percentage of cash flow in POWER TOOLS DEPARTMENT in comparison to the TOTAL CASH FLOW.

Here, Maci is trying to find out the portion of the cash inflow in power tools department with respect to the cash flow of other departments in the hardware store.

The given data represents, the 30% of TOTAL CASH INFLOW = $56,700 and it is in the power tools department.

7 0
3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
3 years ago
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d
kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

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Using the normal distribution table,

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we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

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x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0
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Ugo [173]

Answer:

A. x = 2, y = 7

Step-by-step explanation:

I graphed the equations on the graph below to find the solution to the system of linear equations.

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