The video states that 78% of people carry less than $50 in cash; 40% carry less than $20 in cash, and 9% carry no cash. Suppose you have a random sample of 100 people and you check how much cash each person is carrying. Assuming that the percentages stated in the video are correct for all adult Americans, discuss how it could occur that 12 people in your sample are carrying no cash while only 75 people in your sample are carrying less than $50 in cash.
1 answer:
Answer:
The probability that 12 people in your sample are carrying no cash is 0.0712
Step-by-step explanation:
n = 100
p(no cash) = 0.09
x = 12
By applying binomial distribution
P(x,n) = nCx*px*(1-p)(n-x)
P(x = 12) = 0.074.
The probability that 12 people in your sample are carrying no cash is 0.074.
n = 100
p(less than 50) = 0.78
x = 75
By applying binomial distribution
P(x,n) = nCx*px*(1-p)(n-x)
P(x = 75) = 0.0712
The probability that 12 people in your sample are carrying no cash is 0.0712
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Alright, so 2x+2=0 (with x being the number) is what I'm getting from this. Subtract 2 from both sides to get 2x=-2, and then divide by 2 to get x=-1
Hi GlaxyCraft4991,
Solution:
−12x − 0.4 > 0.2 (36.5x + 80) − 55
−12x − 0.4 > 7.3x − 39
−12x − 0.4 − 7.3x > 7.3x − 39 − 7.3x
−19.3x − 0.4 > −39
−19.3x − 0.4 + 0.4 > −39 + 0.4
−19.3x > −38.6
−19.3x/19.3 > −38.6/19.3
x < 2
Correct Answer:
x < 2
I was going to answer but she gave you the answer sooo
Step-by-step explanation:
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Answer:
these are the answers you need and you'll need it anyways yw
