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KengaRu [80]
3 years ago
11

What is 67 divided by 3,098

Mathematics
2 answers:
Korvikt [17]3 years ago
6 0
0.021626856 . . . . .
erma4kov [3.2K]3 years ago
5 0
The answer is this 0.21626856. btw i used calculator.
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Pls help with math ASAP
9966 [12]
I think 6,1 and the upper point is -6,11
7 0
3 years ago
Which of the following best describes the number shown below?
OLEGan [10]
Irrational

the number is endless in its digits (much like pi) and thus is irrational
5 0
3 years ago
A random sample of n observations is selected from a normal population to test the null hypothesis that muμequals=10. Specify th
brilliants [131]

Answer:

Step-by-step explanation:

a) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 13

Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a two tailed test. Therefore, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

The critical value is 3.012

The rejection region is area > 3.012

b) Ha: μ > 10

This is a right tailed test

n = 23

α = 0.1

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.319

The rejection region is area > 1.319

c) Ha: μ > 10

This is a right tailed test

n = 99

α = 0.05

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.05 = 0.95

The critical value is 1.66

The rejection region is area > 1.66

d) Ha: μ < 10

This is a left tailed test

n = 11

α = 0.1

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.363

The rejection region is area < 1.363

e) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 20

Since α = 0.05, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

The critical value is 2.086

The rejection region is area > 2.086

f) Ha: μ < 10

This is a left tailed test

n = 77

α = 0.01

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.01 = 0.99

The critical value is 2.376

The rejection region is area < 2.376

7 0
3 years ago
Sin(theta/2)=1/2
viva [34]

Part I: sin (theta/2) = 1/2 So, theta/2 = sin inv(1/2) Part II: On the interval [0,2pi], theta/2 = 30 degrees i.e. pi/6 degrees or 150 degrees i.e. 5pi/6...


6 0
3 years ago
Solve for x. −3/4x≥12 Will name brainliest!
Anuta_ua [19.1K]

<em>Answer:</em>

<em></em>\boxed{x \leq -16}<em></em>

<em>Step-by-step explanation:</em>

<em></em>(-\frac{3}{4})^{(x)} \geq 12<em></em>

<em>Simplify both sides of the inequality.</em>

<em></em>\frac{-3}{4} x \geq 12<em></em>

<em>Multiply both sides by 4/(-3).</em>

<em></em>(\frac{4}{-3}) * (\frac{-3}{4}x) \geq  (\frac{4}{-3}) * (12)<em></em>

<em></em>= x \leq -16<em></em>

<em>Hope this helped you!</em>

8 0
3 years ago
Read 2 more answers
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