Answer:
length = 32m, width= 16m
Step-by-step explanation:
l=2w
2(2w+w)=96
2(3w)=96
6w=96,w= 96/6 = 16m
l=2w=2x16=32m
Answer:
Percent increase: 340%
Step-by-step explanation:
Answer:
The pythagorean identity that is correct is option B:
B. tan^2(theta)+1=sec^2(theta)
Step-by-step explanation:
The pythagorean identities are:
1.) sin^2(theta) + cos^2(theta) = 1
2.) tan^2(theta) + 1 = sec^2(theta)
3.) 1 + cot^2(theta) = csc^2(theta)
Then the pythagorean identity that is correct is option B:
B. tan^2(theta)+1=sec^2(theta)
The team has played 24 home games.
Let h be the number of home games and a be the number of away games. The total number of games is 49; this gives ush+a=49
They won 2/3 of the home games and 2/5 of the away games; there were 26 games won. This gives us2/3h + 2/5a = 26
In the first equation we isolate h by subtracting a from both sides:h+a-a=49-ah=49-a
Substitute this into the second equation:2/3(49-a)+2/5a = 26
Using the distributive property, we have2/3*49 - 2/3*a + 2/5a = 2698/3 - 2/3a + 2/5a = 26
Finding a common denominator to combine like terms, we have98/3 - 10/15a + 6/15a = 2698/3 - 4/15a = 26
We want to convert the whole number to thirds as well; 26 = 26*3/3 = 78/3:98/3 - 4/15a = 78/3
Subtracting 98/3 from both sides:98/3 - 4/15a - 98/3 = 78/3 - 98/3-4/15a = -20/3
Divide both sides by -4/15:a = -20/3 ÷ -4/15a = -20/3 × - 15/4 = 300/12 = 25
There were 25 away games.
This means there were 49-25 = 24 home games.
