Copper oxide
As the gas in the air i'm assuming it's Oxygen.
Answer:
ΔT = 20.06 °C
Explanation:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 1.17 kJ = 1170 J
m = mass = 24.1 g
Cp = Specific Heat Capacity = 2.42 J.g⁻¹.°C⁻¹
ΔT = Change in Temperature = <u>??</u>
Solving eq. 1 for ΔT,
ΔT = Q / m Cp
Putting values,
ΔT = 1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹
ΔT = 20.06 °C
Answer:
The answer to your question is length is an extensive property
Explanation:
There are two physical properties: extensive and intensive properties.
An extensive property is a property that depends on the amount of matter.
An intensive property is a property that does not depend on the amount of matter.
Answer:
-200
Explanation:
My sister told me to put dat but dont put dat as your answer
Answer:
P = 34.1 L
Explanation:
Given data:
Number of moles = 10 mol
Volume occupy = 15 L
Temperature = 350°C
Pressure of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
350+273 = 623 K
by putting values,
P×15 L = 10 mol ×0.0821 atm.L/ mol.K ×623 K
P = 511.48atm.L/15L
P = 34.1 L
