aP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m .. Show that AP || BQ. .its a example i just gave.
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-10/16, -20/32. I hope my answer helps. :)
The answer you are looking for is -5x^5-5x^4+6x^3-x^2-7x+20
-I hope this is the answer you are looking for, please feel free to post your future questions on Brainly.com.
Answer:
l = 6
+ 2a - 1
Step-by-step explanation:
the area (A) of a rectangle is calculated as
A = lw ( l is the length and w the width )
given A = 18
+ 6a² - 3a and w = 3a , then
3aw = 18 + 6a² - 3a ( divide each term by 3a )
w = 
+ 
- 
= 6 + 2a - 1
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