The equation is 28/5. George had 6 cookies left over.(estimate.) hope that helped
To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
Use the squeeze theorem; if
1 - <em>x</em> ²/4 ≤ <em>u(x)</em> ≤ 1 + <em>x</em> ²/2,
then taking the limit on each part as <em>x</em> approaches 0 gives
1 ≤ lim [<em>x</em> → 0] <em>u(x)</em> ≤ 1
and so the limit of <em>u(x)</em> as <em>x</em> → 0 is simply 1.
Answer:
B n D
Step-by-step explanation:
Six multiplied by three equals eighteen. fifteen plus three equals eighteen. and eighteen equals eighteen. therefore the equation is equal, because everything in the equation equals eighteen. Good Luck ;)
