For this case we have:
Let a function of the form 
By definition, to graph 
, where 
, we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that 
So, if the black graph is given by, the red graph is given by: 
Answer:
Option A
Dudeeee this is hard. Pick C no balls
You can try to solve it by hit and trial method as x and y are both natural numbers.
x = 5 and y = 2
x+y = 7
Answer: 2:1
Step-by-step explanation:
The ratio of A to B is given by : 
or A : B .
Given : sundaes with nuts = 4
sundaes without nuts = 8
The ratio of the number of sundaes with nuts to the number of sundaes without nuts = ![\dfrac{8}{4}=\dfrac{2}{1}\ \ \ [\text{Divide numerator and denominator by 4 }]](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B4%7D%3D%5Cdfrac%7B2%7D%7B1%7D%5C%20%5C%20%5C%20%5B%5Ctext%7BDivide%20numerator%20and%20denominator%20by%204%20%7D%5D)
= 2:1
hence, the required ratio = 2:1 .
Answer:
The point that divides the directed line segment from J to K into a ratio of 5:1 is (6, 0), its y-coordinate is 0.
Step-by-step explanation:
We take J as point one, with coordinates (x1, y1) = (1, -10) and K as point two with coordinates (x2, y2) = (7, 2)
The "run" is the change in the x-coordinates: x2 - x1 = 7 - 1 = 6
The "rise" is the change in the y-coordinates: y2 - y1 = 2 - (-10) = 12
For the partition ratio, let the numerator = a and the denominator = b.
The coordinates of the point P (x, y), which divides the directed line segment from J to K into a ratio of 5:1 is:
x = x1 + a/(a+b)*run
x = 1 + 5/(5+1)*6
x = 6
y = y1 + a/(a+b)*rise
y = -10 + 5/(5+1)*12
y = 0
