72 total pupils
8x passed the test, x did not
8x + x = 72
9x = 72
x = 8
So since 8x passed the test, substitute 8 for x
8(8) = 64
64 pupils passed the exam
Answer:
3x³ and 6x³, y and 7y
Step-by-step explanation:
Like terms have variables with the same exponents. This fact eliminates choices A, C, D.
The like terms are ...
3x³ and 6x³, 7y and y . . . . . . choice B
<span>Multiply equation A by 2. x+z=6 If you replace the z with the 2, you can add whatever the amount x is to get 6!</span>
Answer:
The minimum score an applicant must receive for admission is 392.
Step-by-step explanation:
Let the minimum score required be 'x₀'.
Given:
Mean score (μ) = 500
Standard deviation (σ) = 100
Percentage required for admission, P > 86% or 0.86
So, we are given the area under the normal distribution curve to the right of z-score which is 86%.
The z-score table gives the area left of the z-score value. So, we will find the z-score value for area 100 - 86 = 14% or 0.14
So, for value equal to 0.1401, the z-score = -1.08
Now, 
So, we find x₀ using the formula of z-score which is given as:

Therefore, the minimum score an applicant must receive for admission is 392.