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3 years ago

HELLPPP

Chemistry

2 answers:

Tpy6a [65]3 years ago

8 0

Answer:

1) oil

2) natural gas

Explanation:

In the transportation industry, oil is the fossil fuel that is mostly used. Oil can be refined to give various petroleum products which are heavily used in the transportation industry such as gasoline, petrol, diesel oil, etc.

In the area of electricity generation, natural gas accounts for 40% of the power generation in the United States of America. About 1582 billion Killo-watt hour of electricity in the United States of America is generated via natural gas. This represents about 40% of the nations total power generation capacity.

joja [24]3 years ago

5 0

Answer 1) Option B) Oil - The fossil fuel that accounts for 95% of consumption for transportation is Oil.

Explanation : Oil is the primary and the majorly used resource for the transportation purposes.
Answer 2) Option A)Petroleum - Petroleum is the fossil fuel that is responsible for 40% of the united state's power generation.

Explanation: Petroleum is considered to be the largest used fossil fuel since its discovery and is been largely used over coal as a substitute.

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This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.

<h3>Combustion:</h3>

In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

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<h3>Calorimetry:</h3>

In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

$Q=mC\Delta T$

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

$m=\frac{Q}{C\Delta T} =\frac{1.415x10^7J}{4.184\frac{J}{g\°C}(100.0\°C-20.0\°C)}\\ \\m=4.227x10^4g$

Finally, we convert it to liters as required:

$V=4.227 x10^4g*\frac{1mL}{1.00g}*\frac{1L}{1000mL} \\\\V=42.27L$

Learn more about calorimetry: brainly.com/question/1407669

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