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Serhud [2]
3 years ago
9

How many moles of gas are in a room with a volume of 85.0 L? A light bulb in the same room at the same temperature and pressure

has a volume of 61.0 L and a 9.00 moles of gas.
Chemistry
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer: A light bulb in the same room at the same temperature.

Explanation: Yw, BYE!!!

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Suppose you want to separate a mixture of the following compounds: salicylic acid, 4-ethylphenol, p-aminoacetophenone, and napth
Elodia [21]

Answer:

The procedure you will use in this exercise exploits the difference in acidity and solubility just described.

(a) you will dissolve your unknown in ethyl acetate (an organic solvent). All of the possible compounds are soluble in ethyl acetate.

(b) you will extract with sodium bicarbonate to remove any carboxylic acid that is present.

(c) you will extract with sodium hydroxide to remove any phenol that is present.

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6 0
3 years ago
which one of the following groups are decomposers a. algae b. protist c. fungi d. green plants e. photosynthetic bacteria
alukav5142 [94]

Answer:c

Explanation:

7 0
2 years ago
38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen
zhuklara [117]
3Si + 2N2 --> Si3N4 (as given) 

n(Si) = m/MM = 38.25/28.085 = 1.3619 mol
n(N2) = 14.33/2*14.007 = 0.5115 mol

Therefore, N2 is limiting and Si is in excess 
The molar ratio of 2N2:Si3N4 is 2:1 
So, 0.0575 mol of silicon nitride is formed (dividing 0.5115 by 2) 

m of silicon nitride= n*mm = 0.0575*140.283 = 8.06627... g 
= 8.066g (4 significant figures) 

(hopefully it is right, but double check in case i did something wrong) :) 
6 0
3 years ago
Carbon tetrachloride, CCl4, was once used as a dry cleaning solvent, but is no longer used because it is carcinogenic. At 57.8 °
Mila [183]
This problem is to use the Claussius-Clapeyron Equation, which is:

ln [p2 / p1] = ΔH/R [1/T2 - 1/T1]

Where p2 and p1 and vapor pressure at estates 2 and 1

ΔH is the enthalpy of vaporization

R is the universal constant of gases = 8.314 J / mol*K

T2 and T1 are the temperatures at the estates 2 and 1.

The  normal boiling point => 1 atm (the pressure of the atmosphere at sea level) = 101,325 kPa

Then p2 = 101.325 kPa
T2 = ?
p1 = 54.0 kPa
T1 = 57.8 °C + 273.15K = 330.95 K
ΔH = 33.05 kJ/mol = 33,050 J/mol 

=> ln [101.325/54.0] = [ (33,050 J/mol) / (8.314 J/mol*K) ] * [1/x - 1/330.95]

=> 0.629349 = 3975.22 [1/x - 1/330.95] = > 1/x =  0.000157 + 1/330.95 = 0.003179

=> x = 314.6 K => 314.6 - 273.15 = 41.5°C

Answer: 41.5 °C 
3 0
3 years ago
Please help ASAP I will give Brainliest
MaRussiya [10]

Answer:

17.6 grams of nitrogen gas

4 0
3 years ago
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