The system is
i)

ii)

The solutions to this system, are all points (x, y) for which BOTH these 2 inequalities hold.
Check the points separately:
(5, 1)
i)

True
ii)

Not True
(0, 0)
i)

True
ii)

True
(-2, -3)
i)

True
ii)

True
(2, 5)
i)

Not True
ii)

Not True
Answer: (0, 0) and (-2, -3)
Answer:
1.5
Step-by-step explanation:
Attached to this answer is the diagram of the box plot described in the question, and the means from the plot are calculated thus;
Students; no. of siblings
student 0 2
student 1 4
student 2 7
student 3 5
student 4 2
Total 20
Mean no. of siblings = (total number of siblings) ÷ (total number of students)
Note that number of students here are the once that had at least one sibling, others without siblings are not used in the calculation, hence 5 students (student-0 to student-4) make up total number of students, while the remaining 4 students (student-4 to student-9) are disregarded.
Therefore, mean = 20 ÷ 5 = 4 siblings.
The answer is 6/10. You have to multiply both the numerator and the denominator by two because the second picture is split in two
Hello :
the polar form is : z = |z
|×e^(iθ)
z=-10+8i
|z | =√((-10)²+(8)²) =<span>√(164)
cos</span>θ = -10/√(164)
sinθ = 8/√(164)
find θ by arctan(8/-10)