Answer:
Step-by-step explanation:
Given
See attachment for graph
Required
The unit cost
Pick any point on the dots of the graph; we have:
The unit cost is then calculated as:
Answer:
3 seconds
Step-by-step explanation:
You want to set h(t)=3, then take the root such that t≠0. You would have:
3=3+48t−16t^2
Let's solve your equation step-by-step.
3=3+48t−16t2
Step 1: Simplify both sides of the equation.
3=−16t2+48t+3
Step 2: Subtract -16t^2+48t+3 from both sides.
3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)
16t2−48t=0
Step 3: Factor left side of equation.
16t(t−3)=0
Step 4: Set factors equal to 0.
16t=0 or t−3=0
t=0 or t=3
3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.
So the ball was in the air for 3 seconds.
Answer:
y = 8x-37
Step-by-step explanation:
y=mx+c
We know the slope m
y=8x+c
We know a point on the line (5,3). Substitute this in for x and y
3 = 8(5) +c
3 = 40+c
3-40 = 40+c-40
-37 =c
y = 8x-37
Answer:
it is 18
Step-by-step explanation:
to find the scale factor divide 48 by 32 to get 1.5, and then multiply the diameter given which is 12, by 1.5 to get 18
The average time the car took to reach each checkpoint are:
<h3>Average time</h3>
Given:
Time interval
1 2 3 4
2.02 3.17 4.12 4.93
2.05 3.07 3.98 4.81
2.15 3.25 4.23 5.01
Hence:
First quarter checkpoint
Average time= (2.02 + 2.05 + 2.15) / 3
Average time=6.22/3
Average time= 2.07s
Second quarter checkpoint
Average time= (3.17 +3.07 + 3.25) / 3
Average time=9.49/3
Average time = 3.16 s
Third quarter check point
Average time= (4.12 + 3.98 + 4.23) / 3
Average time=12.33/3
Average time= 4.11 s
Fourth quarter check point
Average time = (4.93 + 4.81 + 5.01) / 3
Average time=14.75/3
Average time= 4.917 s
Average time=4.92s (Approximately)
Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.
Learn more about average time here:brainly.com/question/19136062
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