Round 4,938,503 to the nearest 100
2 answers:
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X+y=32
xy=-80
x+y=32
minus x both sides
y=32-x
sub for y
x(32-x)=-80
32x-x^2=-80
times both sides by -1
x^2-32x=80
minus 80 both sides
x^2-32x-80=0
use quadratic formula
where
ax^2+bx+c=0
x=
a=1
b=-32
c=-80
x=
x=
x=
x=
x=16+/-4√21
the numbers are
16+4√21 and 16-4√21
xy=-80
x+y=32
minus x both sides
y=32-x
sub for y
x(32-x)=-80
32x-x^2=-80
times both sides by -1
x^2-32x=80
minus 80 both sides
x^2-32x-80=0
use quadratic formula
where
ax^2+bx+c=0
x=
a=1
b=-32
c=-80
x=
x=
x=
x=
x=16+/-4√21
the numbers are
16+4√21 and 16-4√21
<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x
<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)
Since both the distance they traveled are the same, we equate the distance to solve for x.
<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60
<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph
Answer: The spend of the two trains are 60 mph and 108 mph.