“Mud up to the horses’ bellies” is an example of

What's 5x - 4x to the second power + 3 in standees form?

Pani-rosa [81]

(5x - 4x)² + 3

(5x - 4x)(5x - 4x) + 3

Simplify.

25x² - 20x² - 20x² + 16x² + 3

Add like terms.

(25x² - 20x²) + (-20x² + 16x²) + 3

Simplify.

5x² - 4x² + 3

Simplify once more.

x² + 3

~Hope I helped!~

5 0

3 years ago

Evaluate 8 - 4.7y - x <br> when y= -1 and x= 2.

Marat540 [252]

Substitute in the values for y and x into the equation.

so..

8 - 4.7(-1) - (2) solve the equation
8 + 4.7 -2
12.7 - 2
10.7

4 0

3 years ago

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Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Can someone help me solve these four problems.

masya89 [10]

I only know 9.

V = 1

5 0

3 years ago

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Please help me need to revise for a testtt!!!!

LUCKY_DIMON [66]

Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so

3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w

3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2

2x+2x=4x

3 0

3 years ago

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