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Westkost [7]
4 years ago
12

How do you use the vertical line test?

Mathematics
2 answers:
stiks02 [169]4 years ago
7 0
<span>When using the vertical line test, take a ruler or other straight edge and draw a line parallel to the y-axis for any value of x. If the vertical line you drew intersects the graph more than once for any value of x, then the graph is not the graph of a function.</span>
astraxan [27]4 years ago
5 0
<span> is a visual way to determine if a curve is a graph of a function or not.

</span>
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Nate is 10 9/12 years old. How old will he be in 2 1/12 more years?
gayaneshka [121]


To do this, start simple first.

Add 10 and 2

10 + 2 = 12

Now add the fractions:

9/12 + 1/12 = 10/12

Simplify: 5/6

Nate will be 12 and 5/6 years old.

4 0
3 years ago
Read 2 more answers
10-4=6 what is the correct term for the number4
KIM [24]

Answer:

Subtrahend

Step-by-step explanation:

This subtraction problem is in the following form:

Minuend - Subtrahend = Difference

The Subtrahend is the number that is to be subtracted from the Minuend.

In this problem the 10 is the minuend, the 4 is the subtrahend, and 6 is the difference.

~Hope this Helps!~

6 0
3 years ago
47, , 55, 59, , 67 whats the next 2 numbers
zmey [24]

Answer: 75,83

Step-by-step explanation: add by 8 to every number

3 0
3 years ago
Read 2 more answers
If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
S_A_V [24]
Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
3 0
3 years ago
What is the area of a sector with a central angle of 210 degrees and a diameter of 4.6m?
WINSTONCH [101]
Sector area = (central angle / 360) * PI * radius^2
sector area = (210 / 360) * PI * 2.3^2
sector area = (7 / 12) * PI * 5.29
<span><span><span>sector area = 9.6944313302 </span> </span> </span>
<span>sector area = 9.7 square meters (rounded)

Source:
http://www.1728.org/radians.htm

</span>
8 0
3 years ago
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