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sergejj [24]
3 years ago
10

How might the water quality of the stream be affected by changes in the watershed

Biology
1 answer:
bulgar [2K]3 years ago
3 0
Because the stream comes from the watershed, anything being put into the watershed would eventually get into the stream, even if it's a contaminant.
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This recolonization of an area that has been totally destroyed, is an example of... A. climax succeesion B. Pioneer Succession C
d1i1m1o1n [39]

Well Primary Succession means you are the first organisms of that area after it is destroyed completely or if it's new. Secondary Succession is when an area is not destroyed completely but the organisms that remain colonize the area again. I believe it's C.

6 0
3 years ago
Read 2 more answers
The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
3 years ago
I need help as soon as possible​
Hatshy [7]

Answer: 1:3

Explanation: I'm here for you buddy

3 0
3 years ago
Small, oddly shaped bones that fill gaps between bones of the skull are called
netineya [11]
I think they are called Sutural. Intra sutural bones also known as the wormian bones are extra bone pieces that occur within a suture (a joint) in the cranium. They are irregular isolated bones that appears in addition to the usual centers of ossification of the cranium and they are not rare bone despite being unusual.
7 0
3 years ago
A student did an experiment with two identical fish tanks, Tank 1 and Tank 2. About 20 ml water purifier was added to Tank 1 and
maw [93]

Answer:

a . Fish need 10 ml of water purifier to survive.

Explanation:

Fish need 10 ml of water purifier to survive because the data of 10 ml and 20 ml purifier is the same so it is recommended to use 10 ml purifier. First the data was same but by recording next week data, it shows slightly increase in the value of tank 2 while in the last week, both has the same value so we can concluded that by using 10 ml purifier is enough for the fish to survive.

6 0
3 years ago
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