Question

Line segment ba has endpoints b(-6,3) and a(-1,8). What are coordinates of the point located 1/5 of the way from B to A

Answer 1

Answer:

$\vec C = (-5,4)$

Step-by-step explanation:

The coordinates of the point located 1/5 of the way from B to A is:

$\vec C = \vec B + \alpha \cdot \overrightarrow {BA}$

$\vec C = (-6,3) + \frac{1}{5}\cdot (-1+6,8 - 3)$

$\vec C = (-6,3) + \frac{1}{5}\cdot (5,5)$

$\vec C = (-6,3) + (1,1)$

$\vec C = (-6+1,3+1)$

$\vec C = (-5,4)$