Question

Javier and his family drove to see Javier's grandparents during summer vacation in 2006. Gas prices varied from place to place. The gas prices Javier saw advertised advertised during the trip are shown below. What is the difference between the mean and median gas prices in dollars?

Answer 1

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data to calculate the mean and the median are missing.

To solve this, I will assume the following values:

$13, 18, 13, 14, 13, 16, 14, 21, 13$

$n = 9$

The mean is calculated as:

$Mean = \frac{\sum x}{n}$

$Mean = \frac{13+ 18+ 13+ 14+ 13+ 16+ 14+ 21+ 13}{9}$

$Mean = \frac{135}{9}$

$Mean = 15$

To calculate the median;

Start by sorting the data

$Sorted: 13, 13, 13, 13, 14, 14, 16, 18, 21$

$n = 9$

The median is:

$Median = \frac{n + 1}{2}$

$Median = \frac{9 + 1}{2}$

$Median = \frac{10}{2}$

$Median = 5th$

The median is the 5th item on the list; i.e. 14

So:

$Median = 14$

The difference (d) between the mean and the median is:

$d = |Mean - Median|$

$d = |15 -14|$

$d = |1|$

Remove absolute bracket

$d=1$

The difference in the mean and the median of the assumed dataset is 1