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3 years ago

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Freckles are a dominant traitbin humans. Both of the girls have the genotype FF for freckles. Is either one marries a man with n

o freckles,what are the chances that their children will have freckles?

1 answer:

kow [346]3 years ago

6 0

100% because the genotypes for the girls are FF and the man's are ff meaning all children will be Ff with the freckles trait

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3 years ago

Suppose a population of flour beetles has 10,000 individuals. There are two alleles possible for the gene that determines body c

miss Akunina [59]

Answer:

$0.75$

Explanation:

Given frequency of the two alleles i.e "B" and "b" are equal .

As per Hardy–Weinberg equilibrium, sum of frequency of the two alleles is equal to one.

i.e $p+ q= 1\\$

Since $p=q\\$

$p$ and $q$ will be equal to 0.5

Frequency of genotype "BB"

$= p^{2} \\= 0.5^{2} \\= 0.25$

Frequency of genotype "bb"

$= q^{2} \\= 0.5^{2} \\= 0.25$

As per second equation of Hardy–Weinberg equilibrium,

$p^{2} + q^{2} + 2pq=1$

Substituting the values of p and q in above equation we get -

$0.25+0.25+2pq=1\\2pq = 1-0.25-0.25\\2pq = 0.5$

Red beetles have genotype BB and Bb

number of red beetles with genotype (BB)

$= 0.25 * 10000\\= 2500$

number of red beetles with genotype (BB)

$= 0.5 * 10000\\= 5000$

Total red beetles

$2500+ 5000= 7500\\$

Frequency of red beetles

$= \frac{7500}{10000} \\= 0.75$

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