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Oksana_A [137]
3 years ago
13

How do I do this lab report assignment?

Biology
1 answer:
Maslowich3 years ago
6 0
You need a hypothesis a control a non control and experimental class you will have 3 sections and over the days u will record the changes
You might be interested in
A student's grade goes from a 95 to a 65 in 3 weeks. Calculate
steposvetlana [31]

-10grade/week

Explanation:

Given parameters:

Initial grade = 95grade

Final grade = 65grade

Time = 3weeks

Unknown parameter:

Rate of change of grade = ?

Solution:

Rate is defined as the change of a quantity with time.

 Rate of change of grade  = \frac{Final grade - Initial grade}{Time}

Rate of change of grade  = \frac{65 - 95}{3} = \frac{-30}{3}

Rate of change of grade = -10grade/week

The rate of change of the student's grade is -10grade/week. It implies that the grade of the student reduces by 10unit per week.

5 0
3 years ago
) is every minimum bottleneck tree of g a minimum spanning tree of g? prove or give a counter example
mote1985 [20]

The answer is false. To explain further, let G have vertices {v1, v2, v3, v4}, with ends between each pair of vertices, and with the mass on the edge from vi to vj equal to I + j. Then each tree has a bottle neck edge mass of as a minimum of 5, so the tree containing of a track through vertices v3, v2, v1,v4 is a least bottleneck tree. It is not a least spanning tree, though, subsequently its total mass is greater than that of the tree with edges from v1 to every single vertex.

5 0
3 years ago
Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
IgorLugansk [536]

Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

4 0
3 years ago
Which answer is correct?
White raven [17]

Answer:

4

Explanation:

3 0
3 years ago
The mass of an electron is
vodka [1.7K]

Answer:

not significant to the overall mass of the atom

Explanation:

The mass number of an atom is the combination of the mass of the protons and neutrons.  Electrons are not included because their mass are so insignificant that is doesn't change the total mass much, therefore they are left out. The mass of an electron is about 1,830 times smaller than protons and neutrons.

4 0
3 years ago
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