Describe data you can collect and display in both a bar graph and a circle graph.

1 answer:

7 0

A bar graph and a circle graph both show quantitative data. For example, if you take a survey, both graphs can display how many people voted for each choice.

y2-y1/x2-x1
6--1/5-1
6+1/5-1
7/4

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A wise man once said,"500 reduced by 4 times my age is 280." What is his age?

statuscvo [17]

55?

500 - 280 = 220
220/4 = 55
500 - (4x55{his age}) = 280

5 0

3 years ago

Read 2 more answers

Refer to the accompanying technology display. The probabilities in the display were obtained using the values of n equals n=5 an

zubka84 [21]

Answer:

Yes, it is reasonable to expect that more than one subject will experience headaches

Explanation:

Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."

You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.

p = 0.732 is the probability of success (an individual experiences headaches).
n = 5 is the number of trials (number of subjects in the sample).

The meaning of the table of the distribution probability is:

The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.

To answer whether it is reasonable to expect that more than one subject will experience headaches, you must find the probability that:

X = 2 or X = 3 or X = 4 or X = 5

That is:

P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5).

That is also the complement of P(X = 0) or P(X = 1)

1 - P(X = 0) - P(X = 1)

From the table:

P(X = 0) = 0.0014
P(X = 1) = 0.0189

Hence:

1 - P(X = 0) - P(X = 1) = 1 - 0.0014 - 0.0189 = 0.9797

That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.

In conclusion, yes, it is reasonable to expect that more than one subject will experience headaches

6 0

3 years ago

The population of a heard of cattle numbered was 5000 to begin with and was 10,000 after 10 years. If the population was growing

Lapatulllka [165]

Answer:

$r=0.0718$ . The closest value from your given choices is C)r=0.69

Step-by-step explanation:

To solve this we are using the standard exponential growth equation:

$f(t)=A(1+r)^t$

where

$f(t)$ is the final population after $t$ years

$A$ is the initial population

$r$ is the growth rate in decimal form

$t$ is the time in years

We know from our problem that the initial population is 5000, the final population is 10000, and the time is 10 years, so $A=5000$ , $f(t)=10000$ , and $t=10$ .