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2 years ago

What is the slope of the line 2x – 5y = 12 ?

Mathematics

2 answers:

Llana [10]2 years ago

8 0

Answer:

2x−5y=12

y = 2/5x + −12/5

Answer is x = 5/2y + 6 because....

First, Add 5y to both sides.

2x − 5y + 5y = 12 + 5y

Then, Divide both sides by 2.

$\frac{2x}{2} = \frac{5y+12}{2}$

Therefor, your answer is going to be x = 5/2y + 6

* Hopefully this helps:) Mark me the brainliest:)!!!

Darina [25.2K]2 years ago

4 0

Answer:

2/5

Step-by-step explanation:

We are given the following equation of a line and we are to tell the slope of the line:

$2x-5y=12$

We know that the standard equation of a line is given by:

$y = m x + c$ where m is the slope of the line.

So re-writing the given equation in the standard form:

$y=\frac{2}{5} x-\frac{12}{5}$

Therefore, 2/5 is the slope of the line.

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Stolb23 [73]

Answer:

Step-by-step explanation:

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2 years ago

Which is a possible turning point for the continuous function f(x)?

babymother [125]

Answer:

We are given coordinates of a continuous function f(x)

(–2, 0)

(0, –2)

(2, –1)

(4, 0).

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Note: Turning point is a point on the graph where slope of the curve changes from negative to positive or positive to negative.

A turning point is always lowest or highest point of the curve (where bump of the graph seen).

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hoped this was helpful!

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2 years ago

Pick the description of the line x + 3y=1 ? It vertical or horizontal?

Dahasolnce [82]

Given Function: x + 3y=1

Solve into y=mx+b form

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3 years ago

Solve for the variable: 2x - 28 = 16

svlad2 [7]

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2 years ago

Read 2 more answers

A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are

Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

$n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%$

The critical value of z for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)$

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

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2 years ago