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NISA [10]
3 years ago
13

Select the correct answer. Which statement describes the acid found in vinegar (acetic acid)? A. It tastes bitter. B. It feels s

lippery. C. It changes red litmus paper to blue. D. It reacts with Mg to produce H2. E. It releases OH- in a solution.
Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

The acetic acid, (CH_{3}COOH) present in vinegar reacts wit magnesium and therefore, it releases hydrogen gas and magnesium acetate.

The chemical reaction will be as follows.

       2CH_{3}COOH + 2Mg \rightarrow 2Mg(CH_{3}COO) + H_{2}

An acid is a substance which has pH less than 7 and changes blue litmus red. Acids taste sour as they are acidic in nature and releases hydrogen ions.

Whereas bases have pH greater than 7 and changes red litmus into blue.Bases taste bitter and releases hydroxide ions.

Thus, we can conclude that the statement it reacts with Mg to produce H_{2} best describes the acid found in vinegar (acetic acid).

klasskru [66]3 years ago
5 0

Answer:

D. It reacts with Mg to produce H2.

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Identify the missing species in each nuclear equation. Replace the question marks with the appropriate integer or symbol. Be410⟶
astraxan [27]

Answer:

1.  ¹⁰₄Be ---> ¹⁰₅B + ⁰₋₁β

2. ³⁴₁₄Be ---> ³⁴₁₅P + ⁰₋₁β

3. ¹⁹²₇₈Pt -----> ¹⁹⁰₇₆Os + ⁴₂α

4.  ²⁸₁₂Mg ---> ²⁸₁₃Al + ⁰₋₁β

Explanation:

1. In the first equation, Beryllium-10 isotope undergoes beta-decay, emitting a beta-particle to form boron-10 isotope. The balanced nuclear equation is given below:

¹⁰₄Be ---> ¹⁰₅B + ⁰₋₁β

2. In this reaction, silicon-34 isotope undergoes beta-decay, emitting a beta-particle to form phosphorus-34 isotope. The balanced nuclear equation is given below:

³⁴₁₄Be ---> ³⁴₁₅P + ⁰₋₁β

3. In this equation, platinum-192 isotope undergoes alpha-particle decay emitting an alpha-particle to form osmium-190 isotope. The balanced nuclear equation is given below:

¹⁹²₇₈Pt -----> ¹⁹⁰₇₆Os + ⁴₂α

4. In this equation, magnesium-28 isotope undergoes beta-decay, emitting a beta-particle to form aluminum-28 isotope. The balanced nuclear equation is given below:

²⁸₁₂Mg ---> ²⁸₁₃Al + ⁰₋₁β

8 0
3 years ago
What volume of 3.00 M HCl will form a solution with an acidic pH when mixed with 100 mL of 3.00 M NaOH
Maksim231197 [3]

<u>Answer:</u> The volume of acid should be less than 100 mL for a solution to have acidic pH

<u>Explanation:</u>

To calculate the volume of acid needed to neutralize, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH

We are given:

n_1=1\\M_1=3.00M\\V_1=?mL\\n_2=1\\M_2=3.00M\\V_2=100mL

Putting values in above equation, we get:

1\times 3.00\times V_1=1\times 3.00\times 100\\\\V_1=\frac{1\times 3.00\times 100}{1\times 3.00}=100mL

For a solution to be acidic in nature, the pH should be less than the volume of acid needed to neutralize.

Hence, the volume of acid should be less than 100 mL for a solution to have acidic pH

7 0
4 years ago
Hey can someone help me and show work please
Ivahew [28]

Answer: 2.54g

Explanation:

Molar Mass of H2O2 = (2x1) + (2x16) = 34g/mol

1mole (34g) of H2O2 contains 6.02x10^23 molecules

Therefore Xg of H2O2 will contain 4.5x10^22 molecules i.e

Xg of H2O2 = (34x4.5x10^22)/6.02x10^23 = 2.54g

5 0
4 years ago
What is the percent yield for a process in which 10.4g of CH3OH reacts and 10.1 g of CO2 is formed
monitta

Answer:

A. 70.7%

Explanation:

In the first step lets compute the molar mass of CH₃OH and CO

Molar Mass of CH₃OH =  1(12.01 g/mol) + 4(1.008 g/mol) +1(16.00 g/mol)

                                     = 32.042 g/mol

Molar Mass of CO₂      = 1(12.01 g/mol) + 2(16.00 g/mol)  

                                     = 44.01 g/mol

                                   

Mass of only one reactant i.e. CH₃OH is given so  it must be the limiting reactant. Next, the theoretical yield is calculated directly as follows:

Given mass of CH₃OH is 10.4 g. So we have:

                                     10.4g CH₃OH

Convert grams of CH₃OH to moles of CH₃OH utilizing molar mass of CH₃OH as:

                          1 mol CH₃OH / 32.042 g CH₃OH

Convert CH₃OH to moles of CO₂ using mole ratio as:

                             2 mol CO₂ / 2 mol CH₃OH

Convert moles of  CO₂ to grams of  CO₂ utilizing molar mass of  CO₂ as:

                           44.01 g/mol CO₂ / 1 mol CO₂

Now calculating theoretical yield using above steps:

[ 10.4 g CH₃OH ]  [1 mol CH₃OH / 32.042 g CH₃OH ]  [2 mol CO₂ / 2 mol CH₃OH]  [44.01 g/mol CO₂ / 1 mol CO₂]

Multiplication is performed here. We are left with 10.4 and 44.01 g CO₂ from numerator terms in the above equation and 32.042 from denominator terms after cancellation process of above terms. So this equation becomes:

= ( 10.4 ) ( 44.01 ) g CO₂ / 32.042

= 457.704/32/042

=  14.28 g CO₂

Theoretical yield =  14.28 g CO₂  

Finally compute the percent yield for a process in which 10.4g of CH₃OH reacts and 10.1 g of CO₂ is formed:

percent yield = (actual yield / theoretical yield) x 100

As we have calculated theoretical yield which is 14.28 g CO₂ and actual yield is 10.1 g CO₂ So,

percent yield = (10.1 g CO₂ / 14.28 g CO₂) x 100%

                       = 0.707 x 100%

                       = 70.7 %

Hence option A 70.7% yield is the correct answer.

8 0
4 years ago
PLEASE HELPP!
Arada [10]

Answer:

18.18 C

Explanation:

m=55

C=0.45

Q=450zj

ch.temp=?

Q=mct

450 = (55)(.45)T

450 = 24.75

/24.75 = /24.75 (cancels out)

18.18 is the answer

6 0
3 years ago
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