H₂S
<h3>Further explanation</h3>
Given
ΔH fusion and ΔH vaporization of different substances
Required
The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes
Solution
We can use the formula :
Q=heat/energy absorbed
n = moles
The heat absorbed : 58.16 kJ
moles = 3.11
so ΔH vaporization :
The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S
(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)
Answer:
The correct answer is B) HOOCCH2CH2COOH(aq)
Explanation:
Both Ka1 and Ka2 are low, so the acid will dissociate only slightly into HOOCCH2CH2COO- ions and even more slightly into -OOCCH2CH2COO- ions. The concentration of hydronium ions (H₃O⁺) will be consequently low. The species that will be in the highest concentration will be HOOCCH2CH2COOH (the weak acid not dissociated).
I assume that it is herring
Answer:
1)alkali metals
2)1g/ml
3) mercury
Explanation:
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Answer: [Kr] 5s1 4d10 silver
[Xe] 6s2 4f14 5d7 Iridium
[Ar] 4s2 3d10 4p4 selenium
[Kr] 5s1 4d4 niobium
[Xe] 6s1 4f14 5d10 gold
[Kr] 5s2 4d10 5p4 tellurium
Explanation:
Selenium and tellurium will have the same properties because they both belong to group 16 in the periodic table.
Silver and gold will have the same properties because they both belong the group 11 in the periodic table.
Elements having the same outermost shell configuration show similar properties since chemical reactions occur by loss or gain of electrons. This loss or gain is determined by the number of electrons occupying the outermost shell. Elements in the same group have the same outermost shell electron configuration and similar properties.
