C + 1/2O2 => CO
Monoxide is forming if there is no enough oxigen to combine with
Answer:
The second law of thermodynamics.
Explanation:
The global transfer of energy from fuels to electricity is about 35% efficient is most likely a consequence of the second law of thermodynamics. This second law states that as energy is transformed more it is wasted, also that the entropy of a system remains constant or increase, but never decrease over time. That is why is impossible to convert heat energy to mechanical with 100 % efficiency.
Therefore, in the production of electricity, a minor part of chemical energy (from fuels) will be transformed into energy and the rest will be lost to the environment, mostly as heat, to satisfy the second law of thermodynamics.
I hope it helps you!
Answer:
SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)
Explanation:
Let's consider the molecular equation that occurs when aqueous solutions of ammonium sulfate and barium nitrate are mixed.
(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) ⇒ BaSO₄(s) + 2 NH₄NO₃(aq)
The complete ionic equation includes all the ions and insoluble species.
2 NH₄⁺(aq) + SO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) ⇒ BaSO₄(s) + 2 NH₄⁺(aq) + 2 NO₃⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and the insoluble species.
SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)
Answer:
0.59 moles
Explanation:
Data Given
oxygen = 35 g
Moles of SeO₃ = ?
Reaction Given
2Se + 3O₂ ------> 2SeO₃
Solution:
Step 1.
First to find grams of SeO₃
So, we know from reaction that 2 mole of selenium combine with 3 mole of oxygen and produces 2 mole of SeO₃
2Se + 3O₂ ------> 2SeO₃
2mol 3 mol 2 mol
If we represent mole in grams
Then,
Molar mass of Se = 79 g/mol
Molar mass of O = 16 g/mol
Molar mass of SeO₃ = 79 + 3(16)
Molar mass of SeO₃ = 127 g/mol
2Se + 3O₂ ------> 2SeO₃
2mol (79 g/mol) 3 mol (32 g/mol) 2 mol (127 g/mol)
2Se + 3O₂ ------> 2SeO₃
158 g 96 g 206 g
It is obvious from the reaction that 96 g of oxygen gives 206 g of SeO₃.
Now how many grams of SeO₃ will produce if 35 grams of oxygen react with excess of Selenium
Apply unity formula
96 g of O₂ ≅ 206 g of SeO₃
35 g of O₂ ≅ x g of SeO₃
By doing cross multiplication
g of SeO₃ = 206 x 35 / 96
g of SeO₃ = 75 g
Step 2.
Convert grams of SeO₃ to mole
Formula used
no. of moles = mass in grams (SeO₃) / Molar mass of SeO₃
Put values in above formula
no. of moles = 75 g / 127 g/mol
no. of moles = 0.59 mol
So,
35 g of oxygen produces 0.59 moles of SeO₃
