Question

If x and y are real numbers what is the simplified radical form of x^2y^5

Answer 1

X, y ∈ R

$x^{2}y^{5}\\\\ \sqrt{x^{2}y^{5}} = \sqrt{x^{2}*y*y^{4}}= \sqrt{x^{2}*y*({y^{2})^{2}} }=xy^{2} \sqrt{y}$