(4x3+2x+6)+(2x3-x2+2)
Final result :
6x3 - x2 + 2x + 8
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 2 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((4•(x3))+2x)+6)+((2x3-x2)+2)
Step 2 :
Equation at the end of step 2 :
((22x3 + 2x) + 6) + (2x3 - x2 + 2)
Step 3 :
Checking for a perfect cube :
3.1 6x3-x2+2x+8 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 6x3-x2+2x+8
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 2x+8
Group 2: 6x3-x2
Pull out from each group separately :
Group 1: (x+4) • (2)
Group 2: (6x-1) • (x2)
The answer will be B.exponential
Answer:
(3 7/8, -1 3/4)
Step-by-step explanation:
The midpoint is the average of the end point coordinates:
((5 1/2, -4 3/4) +(2 1/4, 1 1/4))/2
= (7 3/4, -3 1/2)/2 = (3 7/8, -1 3/4)
Answer:
A
Step-by-step explanation:
Given
4n² + 4(4m³ + 4n² ) ← distribute terms in parenthesis by 4
= 4n² + 16m³ + 16n² ← collect like terms
= (4n² + 16n²) + 16m³
= 20n² + 16m³
= 16m³ + 20n² ← in standard form → A
