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3 years ago

The Polygon Angle-Sum Theorem states the following: The sum of the measures of the angles of an n-gon is ____.

Mathematics

1 answer:

larisa [96]3 years ago

6 0

A triangle has 3 sides and angle sum of 180 so ( 3 - 2)*180 = 180 so it seems to work.

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5-7+6+(-3)-1-(-8) simplify

Airida [17]

Your answer would be 5−7+6−3−1−(−8) = 8

6 0

4 years ago

Fill in the missing numbers I need an answer ASAP

mamaluj [8]

Answer:

the missing numbers be 60 and 6 respectively

Step-by-step explanation:

The computation of the missing numbers are shown below:

Let us assume the missing numbers be x

, $\frac{1}{2} \times 30 = \frac{1}{4} \times x\\\\15 = \frac{1}{4} \times x\\\\x = 60$

$\frac{1}{3} \times 12 = \frac{2}{3} \times x\\\\4 = \frac{2}{3} \times x\\\\x = 6$

Hence, the missing numbers be 60 and 6 respectively

4 0

3 years ago

Need help quick ASAP!!!!! Please!!!!!

jarptica [38.1K]

The answer is B. I have this question before when i was in 3rd grade once. u must be in k12

3 0

3 years ago

Read 2 more answers

Leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. The triangular base has a

almond37 [142]

Answer:

A. $x=\frac{-7+\sqrt{193}}{4}$

Step-by-step explanation:

We have, the dimensions of the living room are 30 ft and 20 ft.

Thus, area of the living room = length × width = 30 × 20 = 600 ft².

Now, it is given that the cabinet takes 6% of the living room i.e. 6% of 600 ft² = 0.06 × 600 = 36 ft².

As, the triangle has dimensions (2x+3) ft and (3x+6) ft.

So, the area of the triangle = $\frac{1}{2}\times base\times height$

i.e. Area of cabinet = $\frac{1}{2}\times (2x+3)\times (3x+6)$

i.e. Area of cabinet = $\frac{3}{2}\times (2x+3)\times (x+2)$

i.e. Area of cabinet = $\frac{3}{2}\times (2x^2+7x+6)$

Since, the cabinet takes 6% of the living room, we have,

$\frac{3}{2}\times (2x^2+7x+6)$ = 36

i.e. $2x^2+7x+6=36\times \frac{2}{3}$

i.e. $2x^2+7x+6=24$

i.e. $2x^2+7x-18=0$

Further, as the solution of a quadratic equation $ax^{2}+bx+c=0$ is given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

On comparing we have, a=2, b=7, c= -18.

Thus, $x=\frac{-7\pm \sqrt{7^{2}-4\times 2\times (-18)}}{2\times 2}$

i.e. $x=\frac{-7\pm \sqrt{49+144}}{4}$

i.e. $x=\frac{-7\pm \sqrt{193}}{4}$

i.e. $x=\frac{-7+\sqrt{193}}{4}$ and $x=\frac{-7-\sqrt{193}}{4}$

So, according to the options, we have,

A. $x=\frac{-7+\sqrt{193}}{4}$ is the correct value of x.

7 0

3 years ago

Please help me please i really need help please

grandymaker [24]

9514 1404 393

Answer:

62°

Step-by-step explanation:

Angles A and H are alternate exterior angles, so are congruent.

∠H = 62°

6 0

3 years ago