Answer:
-7.2
Step-by-step explanation:
Since -3.2 is the first number, this will be the starting point in the number line.
Since we are subtracting, we are going to go 4 units to the left.
-3.2 - 4 = -7.2
Best of Luck!
Answer:
12/16 = 3/4
I divided both sides by 4.
Hope this helps!
-Mikayla
Since tyler has 83 football cards we can divided, 83 divided by 6 cards for each page would have 13 cards, and he would have an extra page making 14 with the last one containing 5 left over cards, this would leave one space left over for new cards.
Answer:
12
Step-by-step explanation:
Given: Diagonal of square= 
To find the perimeter of square, we need to find the length of sides of square.
∴ Using the formula of diagonal to find side of square.
Formula; 
Where, s is side of square.
⇒ 
Dividing both side by √2
⇒
∴
Hence, Length of side of square is 3.
Now, finding the perimeter of square.
Formula; 
⇒
∴ 
Hence, Perimeter of square is 12.
The <em><u>correct answer</u></em> is:
x³+x²+x+1.
Explanation:
First we write the polynomial out with all of the other powers of x, using 0 as their coefficients:
(1x⁴+0x³+0x²+0x-1)÷(x-1)
To perform synthetic division, we write the coefficients of the dividend in a row:
1 0 0 0 1
We take the 1 from x-1 and use it in the box. We then drop the first 1 from the row of coefficients down.
We multiply our 1 in the box by the 1 at the bottom; this is 1 and goes under the first 0 to the right of the 1 in the coefficients row. We now add this 0+1; this is 1 and goes at the bottom beside the other 1.
Multiply this by 1; this is 1 and goes under the second 0 from the left in the row of coefficients. Add this to the 0; this is 1 and goes at the bottom, to the right of the other two 1's.
Multiply this by 1; this is 1 and goes under the third and last 0 in the row of coefficients. Add this to the 0; this is 1 and goes at the bottom, to the right of the other three 1's.
Multiply this by 1; this is 1 and goes under the -1 in the row of coefficients. Add this to the -1; this is 0 and goes at the bottom, to the right of the four 1's. This 0 means there is no remainder and the quotient was evenly divided. It gives us
1 1 1 1 0
This means we have 1x³+1x²+1x+1 with no remainder.