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defon
3 years ago
8

Can y’all please helpppp!

Mathematics
1 answer:
Rudiy273 years ago
8 0

Answer:

1) x= 35 , y = 18

2) x = 20 , y = 23.33

3) x = 11

4) x = 9

5) x = 10

Step-by-step explanation:

1)As the triangles are similar, here the ratio is as;

\frac{JK}{NM} = \frac{KL}{ML}  = \frac{LJ}{LN}

 \frac{40}{16} = \frac{x}{14}  = \frac{45}{y}

from here, x=35 and y = 18

2)As the triangles are similar, here the ratio is;

\frac{DE}{HJ} = \frac{EF}{JG}  = \frac{FD}{GH}

 \frac{9}{15} = \frac{14}{y}  = \frac{12}{x}

from here, x=20 and y= 23.33

3)As the triangles are similar, here the ratio is;

  \frac{QR}{TU} = \frac{RS}{UV}

  \frac{24}{x +5} = \frac{54}{36} here, x = 114)As the triangles are similar, here the ratio is;    [tex]\frac{AB}{AD} = \frac{BC}{DE}

    \frac{28}{20} = \frac{2x+3}{15}

here, x = 9

5)As the triangles are similar, here the ratio is;

\frac{NP}{RP} = \frac{MP}{QP}

\frac{x+8}{3x-9} = \frac{24}{28},

from here, x = 10

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A child lets go of a balloon that rises at a constant rate. 5 seconds after it was released, the balloon is at a height of 16 fe
Mama L [17]

Answer:

1. h = 2.4t + 4

2. 4 feet

3. 220 feet

Step-by-step explanation:

1. Write a linear model for the height, h, of the balloon as a function of the number of seconds, s that it has been raising.

Since the balloon rises at a constant rate, we find this rate by using the initial and final values of height and time at 5 seconds and 20 seconds respectively which are 12 feet and 52 feet respectively.

So, rate = gradient of line

= change in height/change  in time

= (52 ft - 16 ft)/(20 s - 5 s)

= 36 ft/15 s

= 2.4 ft/s

Now the equation of the line which shows the height is gotten from

(h - h')/(t - t') = rate

Using h'= 16 feet and t' = 5 s, we have

(h - 16)/(t - 5) = 2.4

h - 16 = 2.4(t - 5)

h - 16 = 2.4t - 12

h = 2.4t - 12 + 16

h = 2.4t + 4

where h is the height of the balloon above the ground and t is the time spent in the air in seconds.

2. What was the height of the balloon initially before the child let it go?

We obtain the initial height of the balloon before the child let go at time, t = 0 the time before the child let go.

So, substituting t = 0 into the equation for h, we have

h = 2.4t + 4

h = 2.4(0) + 4

h = 0 + 4

h = 4 feet

So, the height of the balloon before the child let go is 4 feet above the ground.

3. Use your model to predict the height of the balloon after 90 seconds.

We insert t = 90 s into the equation for h. So,

h = 2.4t + 4

h = 2.4(90) + 4

h = 216 + 4

h = 220 feet

So, the height of the balloon after 90 s is 220 feet above the ground.

8 0
2 years ago
Solve for x.<br><br> 0.5x + 78.2 = 287
vladimir2022 [97]
0.5x + 78.2 = 287
          -78.2  -78.2

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3 0
3 years ago
Read 2 more answers
3 times (-8) times (-2)
dexar [7]

Answer:

48

Step-by-step explanation:

Signals during a multiplication of two numbers:

They have the same signal: The multiplication is positive.

They have different signals: The multiplication is negative.

3 times (-8) times (-2)​

First 3*(-8):

Different signals, so negative. 3*8 = 24. So the answer is -24.

Then:

3*(-8)*(-2) = (-24)*(-2)

Same signal, so positive. 24*2 = 48. The answer is 48.

4 0
1 year ago
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Ivahew [28]

........Option C ) n × 2 = t

8 0
2 years ago
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City park is a right triangle with a base of 49 yrds and a height of 25 yard in a map The park is a basic 3 inches and the heigh
ASHA 777 [7]

Answer:

3/49

Step-by-step explanation:

The area of a rectangle is found using A = l*w. At the park, it measures A = 49*25 = 1,225 yards².

On the map the area is A = 3*25 = 75 inches².

The ratio of the area of the map to the area of the park is found by placing 75 ovre 1,225. Then simplify if possible.

\frac{75}{1225} = \frac{3*25}{49*25} = \frac{3}{49}

7 0
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