Question

A chemistry student needs of -bromobutane for an experiment. She has available of a w/w solution of -bromobutane in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to significant digits.

Answer 1

Question

A chemistry student needs 15.00g of bromobutane for an experiment. She has available 220.g of a 30.2% w/w solution of bromobutane in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Round your answer to 5 significant digits.

Answer:

49.669g

Explanation:

Given

220 g of solution has 30.2% w/w bromobutane

15.00g of bromobutane needed?

Required

Since the 220g solution has 30.2% w/w bromobutane

Then

The solution has 0.302 * 220

= 66.44g of bromobutane

From here. We can Calculate the expected grams required for 15.0g of bromobutane

, if 220 g of solution contains 66.44 g bromobutane,

The 15.0g will contain

=>

       220 g solution = 66.44 g bromobutane

        Y g solution = 15.00 g bromobutane

-----------Credit Multiply-----_-----

Y * 66.44 = 15 * 220

Y * 66.44 = 3300 ------- Divide both sides by 66.44

Y = 3300/66.44

Y = 49.66887g

Y = 49.669g --------- Approximated

The student should use 49.669g of the solution