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yarga [219]
3 years ago
11

How to do this problem??

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0
We know that the sum of the inner angles of any triangle is 180º

72º + (7x + 3)º + (3x + 5)º = 180º
72º + 7xº + 3º + 3xº + 5º = 180
7xº + 3xº = 180º - 72º - 3º - 5º
10xº = 100º
x^0 =  \frac{100^0}{10^0}
x^0 = 10\to\:\boxed{\boxed{x = 10^0}}\end{array}}\qquad\quad\checkmark

The sum of the external angle (9y + 1)º with inner angle (3x + 5) = 180 °, <span>Replace the measure of "x" found:
</span>
(9y + 1)º + (3x + 5)º = 180º
9yº + 1º + 3xº + 5º = 180º
9yº + 1º + 3.(10)º + 5º = 180º
9yº + 1º + 30º + 5º = 180º
9yº = 180º - 1º - 30º - 5º
9yº = 144º
y^0 =  \frac{144^0}{9^0}
y^0 = 16\to\:\boxed{\boxed{y = 16^0}}\end{array}}\qquad\quad\checkmark

Answer:
<span>The measures ​​of "x" and "y" are respectively: 10º and 16º</span>
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