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alexandr402 [8]
3 years ago
11

Y-1=5/6(x-4) in standard form

Mathematics
2 answers:
scoray [572]3 years ago
8 0
           y - 1 = ⁵/₆(x - 4)
           y - 1 = ⁵/₆(x) - ⁵/₆(4)
           y - 1 = ⁵/₆x - 3¹/₃
             + 1         + 1
                 y = ⁵/₆x - 2¹/₃
        ⁻⁵/₆x + y = ⁵/₆x - ⁵/₆x - 2¹/₃
   -6(⁻⁵/₆x + y) = -6(-2¹/₃)
-6(⁻⁵/₆x) - 6(y) = 14
         5x - 6y = 14
Tresset [83]3 years ago
8 0
If you would like to write the equation Y - 1 = 5/6 * (x - 4) in standard form, you can do this using the following steps:

Y - 1 = 5/6 * (x - 4)
Y - 1 = 5/6 * x - 5/6 * 4
Y - 1 = 5/6 * x - 10/3
Y - 5/6 * x = 1 - 10/3
Y - 5/6 * x = - 7/3       /*6
6 * Y - 5 * x = - 14

The correct result would be 6 * Y - 5 * x = - 14.
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Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Aliun [14]
《ANSWER》

《LINEAR EQUATIONS》

Solving all we get as

↪1) 5 (x -2) = 5x - 7

since after solving X is cancelled , NO SOLUTION

↪2) -3 (x - 4) = -3x + 12

SINCE after solving X is any value , infinitely many solutions

↪3) 4 (x + 1) = 3x + 4

solving we get as , 4x+ 4 = 3x + 4 =》 X =0

only one solution

↪4) -2 (x-3) = 2x - 6

Only one solution

↪5) 6 (x + 5) = 6x + 11

NO SOLUTION

All the equations are solved by the distributive law of algebra
5 0
3 years ago
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WILL MARK BRAINLEST ! HELP! THANK YOU!
Bond [772]

Answer:

By definition of congruence

Step-by-step explanation:

Triangle ABC is congruent to triangle DBE

7 0
3 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

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Answer:

Step-by-step explanation:

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so,

88 feet/second

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135 feet means that it reached the river within 2 seconds. it reached the river in 1.545 seconds

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Answer:

x > 10

Step-by-step explanation:

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