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2 years ago

Y-1=5/6(x-4) in standard form

2 answers:

8 0

   y - 1 = ⁵/₆(x - 4)
   y - 1 = ⁵/₆(x) - ⁵/₆(4)
   y - 1 = ⁵/₆x - 3¹/₃
   + 1    + 1
             y = ⁵/₆x - 2¹/₃
      ⁻⁵/₆x + y = ⁵/₆x - ⁵/₆x - 2¹/₃
   -6(⁻⁵/₆x + y) = -6(-2¹/₃)
-6(⁻⁵/₆x) - 6(y) = 14
         5x - 6y = 14

Tresset [83]2 years ago

8 0

If you would like to write the equation Y - 1 = 5/6 * (x - 4) in standard form, you can do this using the following steps:

Y - 1 = 5/6 * (x - 4)
Y - 1 = 5/6 * x - 5/6 * 4
Y - 1 = 5/6 * x - 10/3
Y - 5/6 * x = 1 - 10/3
Y - 5/6 * x = - 7/3 /*6
6 * Y - 5 * x = - 14

The correct result would be 6 * Y - 5 * x = - 14.

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Drag the expressions to the correct functions. Not all expressions will be used.

postnew [5]

The function composition exists an operation " ∘ " that brings two functions f and g, and has a function h = g ∘ f such that h(x) = g(f(x)).

Let the functions be f(x) = 4x² + 1 and g(x) = x² - 3

The correct answer is (f o g)(x) = 4x⁴ - 96x + 37 and

(g o f)(x) = 16x⁴ + 8x² - 2.

<h3>What is composition function?</h3>

The function composition exists an operation " ∘ " that brings two functions f and g, and has a function h = g ∘ f such that h(x) = g(f(x)). In this operation, the function g exists used for the outcome of applying the function f to x.

Given:

f(x) = 4x² + 1 and g(x) = x² - 3

a) (f o g)(x) = f[g(x)]

f[g(x)] = 4(x² - 3)² + 1

substitute the value of g(x) in the above equation, and we get

= 4(x⁴ - 24x + 9) + 1

simplifying the above equation

= 4x⁴ - 96x + 36 + 1

= 4x⁴ - 96x + 37

(f o g)(x) = 4x⁴ - 96x + 37

b) (g o f)(x) = g[f(x)]

substitute the value of g(x) in the above equation, and we get

g[f(x)] = (4x² + 1)²- 3

= 16x⁴ + 8x² + 1 - 3

simplifying the above equation

= 16x⁴ + 8x² - 2

(g o f)(x) = 16x⁴ + 8x² - 2.

Therefore, the correct answer is (f o g)(x) = 4x⁴ - 96x + 37 and

(g o f)(x) = 16x⁴ + 8x² - 2.

To learn more about the function refer to:

brainly.com/question/26709985

#SPJ9

7 0

1 year ago

Leap years are years in which February has 29 days instead of 28. The device of leap year was invented to keep the calendar in s

goldenfox [79]

Answer:

As you know, a year has around 365 + 1/4 days.

This means that in two years, we have:

365 + 356 + 1/4 + 1/4 = 730 + 1/2

and so on.

adding this up, when we have 4 years we have a full day extra, this is:

1460 + 1

When we divide 1461 by 4, we have 365 with a surpass of 1.

The rule used to keep the calendar in sync with this extra day is adding an extra day to each fourth year.

So each fourth year, we have an extra day in Februray (the Februray 29th), this is called a bisiest year.

The "math rule" used to know if a year is leap or not is:

if a year is not divisible by 4, then it is a common year

else if the year is not divisible by 100 then it is a leap year,

else if the year is not divisible by 400, then it is a common year

if not, the year is a leap year.

Where "year" represents the number of the year.

8 0

2 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago

An equation is shown.

lubasha [3.4K]

<span>2(a+b)=c
2a + 2b = c
2b = c - 2a
b = (c - 2a)/a

answer
</span><span>D. b = (c−2a)/2 ; distribute 2 to get 2a+2b, subtract 2a, then divide by 2.</span>

3 0

2 years ago

The ratio of the number of students in the golf club to the number of students on the swim team is 1:3 the ratio of the number o

zavuch27 [327]

Answer:

gfgdgggfbgfgfhgfdhhgf

Step-by-step explanation:

gfg

6 0

3 years ago