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Norma-Jean [14]
3 years ago
11

4,275,000,000 in scientific notation

Mathematics
1 answer:
Leni [432]3 years ago
6 0
4.275x10^{9}
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Please help asap :( "This is My final Grade " My Teacher wants a full explanation included with the answer .) please view the at
STALIN [3.7K]

Answer:

Step-by-step explanation:

circle A is

x²+y²+6x-4y-12=0

x²+6x +y²-4y =12

think (a+b)² = a²+2ab+b² we have a=x, b= 3

and (a-b)² = a²-2ab+b² so we have a=y, b=2

x²+6x +9 +y²-4y+4 = 12-9-4

(x+3)² +(y-2)²= -1

compare to the general equation of a circle (x-h)²+(y-k)² =r²

the center is at (-3,2) and the radius is √-1 =i

Circle B has center (0, -4) and radius 3 so the equation is

(x-0)²+(y-(-4))² =3²

x² +(y+4)² = 9

point (√8, -3) is on the circle if it verifies the equation

√8² +(-3+4)² = 9

8+1 =9 true so the point is on the circle

Circle A and circle B are not similar because they do not have the same center and radius

4 0
3 years ago
1Y, the number of accidents per year at a given intersection, is assumed to have a Poisson distribution. Over the past few years
miss Akunina [59]

Answer:

The probability that the intersection will come under the emergency program is 0.1587.

Step-by-step explanation:

Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.

Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.

For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.

Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

W = \frac{X-\mu}{\sigma} = \frac{X-3}{1/2} = 2x-6

The values of \phi , the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program

P(X > 3.75) = P(2X-6 > 2*3.75-6) = P(W > 1) = 1-\phi(1) = 1-0.8413 \\= 0.1587

Download pdf
7 0
3 years ago
Write an equation of a line with the given slope and y-intercept. m = –2, b = 4
Verdich [7]
Y= -2x+4 m represents the x value and b the y intercept
4 0
3 years ago
Read 2 more answers
Evaluate each expression <br><br> 10 (e+7)<br> E=3
Nostrana [21]
Plug in e for 3.

10(3+7)

Use the distributive property. a(b+c)= ab+ac

10*3= 30, 10*7=70

30+70=100

The expression equals 100.

I hope this helps!
~kaikers
5 0
3 years ago
Read 2 more answers
Debby pays rent twice a year, buys groceries once every quarter, and buys a transit pass
Natasha2012 [34]
<h3>Answer: 2x+4y+12z (choice B)</h3>

Work Shown:

x = amount of rent paid per half year

2x = amount of rent paid annually

y = amount spent on groceries per quarter

4y = amount spent on groceries annually

z = amount spent on a transit pass monthly

12z = amount spent on transit pass annually

2x+4y+12z = total amount of money spent annually

8 0
3 years ago
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