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1 year ago

What triangle congruence postulate would you use to prove these triangles are congruent.

Mathematics

2 answers:

masha68 [24]1 year ago

5 0

Ssssssssssssssssssssss

swat321 year ago

4 0

Answer:

I don't know

Step-by-step explanation:

sorry

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Jackson played a video game for 1/6 for hour. Hailey played a video game for 1/3 hour. Who played the video game for a greater a

viva [34]

Answer:

hailey played the game longer (1/3 hour).

Step-by-step explanation:

You are deciding which is greater: 1/6 or 1/3.in this case, a smaller denominator (such as 3) produces a greater value.1/3 has a smaller denom. than does 1/6, so 1/3 is greater than 1/6.hailey played the game longer (1/3 hour).

5 0

2 years ago

In circle O, what is mArc A E?

posledela

Answer:

Option (3). 120° will be the answer.

Step-by-step explanation:

By using the theorem of secants intersecting externally,

Measure of angle formed by two secants, from a point outside the circle is half the difference of the measures of the intercepted arcs.

m∠C = $\frac{1}{2}(m\widehat{AE}-m\widehat{BD})$

36° = $\frac{1}{2}(m\widehat{AE}-48)$

72° = $m\widehat{AE}-48$ °

$m\widehat{AE}$ = 72 + 48

$m\widehat{AE}$ = 120°

Therefore, Option (3) is the answer.

7 0

2 years ago

Fill in the blank. 7.5 km = m

Ganezh [65]

Answer:

7500

Step-by-step explanation:

7 0

2 years ago

The height of a soccer ball is kicked from the ground can be approximately by the function.

stira [4]

Answer:

1 second

Step-by-step explanation:

y = -16x² + 32x

y = -16(x² - 2x)

y = -16(x² - 2(x)(1) + 1² - 1²)

y = -16(x - 1)² + 16

Max height is when (x-1) = 0

So x = 1

4 0

2 years ago

Help me with this please!!

valina [46]

<h2><u>Given:</u><u>-</u></h2>

Points C = (-7,2) → $\sf{(X_1,Y_1)}$
D = (3,12) → $\sf{(X_2,Y_2)}$

The Midpoint of CD.

<h2><u>Required</u><u> </u><u>Response</u><u>:</u><u>-</u></h2>

Let,

Midpoint of CD be (x,y).

WKT,

$\boxed{\sf{(x,y) = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}$

$→\;{\sf{\frac{-7+3}{2},\frac{2+12}{2}}}$

$→\;{\sf{\frac{-4}{2},\frac{14}{2}}}$

$→\;{\sf{-2,7}}$

The Midpoint of CD ◕➜ $\Large{\red{\mathfrak{(-2,7)}}}$

Let,

The centre be O

Radius = CO & OD

Here, C = (-7,2) → $\sf{(X_1,Y_1)}$

O = (-2,7) → $\sf{(X_2,Y_2)}$

$\boxed{\sf{Distance = \sqrt{(X_2-X_1)²+(Y_2-Y_1)²}}}$

$→\;{\sf{\sqrt{(-2+7)²+(7-2)²}}}$

$→\;{\sf{\sqrt{5²+5²}}}$

$→\;{\sf{\sqrt{25+25}}}$

$→\;{\sf{\sqrt{50}}}$

$→\;{\sf{5√2 (or) 7.07}}$

Radius of Circle ◕➜ $\Large{\red{\mathfrak{7.07}}}$

<h2>Option D.</h2>

Hope It Helps You ✌️

3 0

2 years ago